(2x^2)+(4x)+42=0

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Solution for (2x^2)+(4x)+42=0 equation: 



(2x^2)+(4x)+42=0

a = 2; b = 4; c = +42;
Δ = b2-4ac
Δ = 42-4·2·42
Δ = -320
Delta is less than zero, so there is no solution for the equation

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